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Atomic structure & bonding

Atomic structure basics

  • Atoms have protons (+1, mass 1) and neutrons (0, mass 1) in the nucleus, with electrons (-1, negligible mass) in shells around it.
  • Atomic number (Z) = number of protons = number of electrons in a neutral atom.
  • Mass number (A) = protons + neutrons.
  • Isotopes have the same Z but different A (different neutron numbers) — same chemical properties, slightly different physical ones.
  • Relative atomic mass (Ar) is a weighted mean based on isotopic abundance, measured relative to carbon-12.

Electron configuration

  • Electrons fill orbitals in order of increasing energy: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p.
  • Sub-shells hold a fixed maximum: s = 2 electrons, p = 6, d = 10, f = 14.
  • Orbitals within a sub-shell are filled singly first (Hund's rule) before pairing up.
  • Watch for the exam favourite: 4s fills before 3d, but empties first when forming transition metal ions (so Fe is [Ar]3d6 4s2 but Fe2+ is [Ar]3d6, not 3d4 4s2).
  • Chromium and copper are exceptions: Cr is [Ar]3d5 4s1 and Cu is [Ar]3d10 4s1, because a half-full or full d sub-shell is extra stable.

Ionisation energy

  • First ionisation energy is the energy needed to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions.
  • Successive ionisation energies always increase, since removing an electron from an increasingly positive ion needs more energy.
  • Big jumps between successive ionisation energies show a change of shell — this is the classic evidence question for shell structure.
  • Across a period, ionisation energy generally rises (more protons, same shell), but drops slightly at group 3 (start of p sub-shell, easier to remove) and group 6 (electron pairing repulsion).
  • Down a group, ionisation energy falls because atomic radius increases and shielding increases, outweighing the extra protons.

Bonding

  • Ionic bonding: electrostatic attraction between oppositely charged ions in a giant lattice; strong in all directions, high melting points, conducts only when molten or dissolved.
  • Covalent bonding: shared pair of electrons between two atoms; can be simple molecular (low melting point, doesn't conduct) or giant covalent like diamond and graphite (very high melting point).
  • Metallic bonding: delocalised electrons attract a lattice of positive metal ions; conducts as a solid and liquid, malleable because layers of ions can slide.
  • Dative (coordinate) bonding: both shared electrons come from the same atom, shown with an arrow, e.g. in NH4+ or Al2Cl6.

Common mistakes

  • Don't say 'electrons are lost to space' — always state the products form gaseous ions.
  • Always give ionisation energy definitions in full with 'one mole' and 'gaseous' — examiners mark this strictly.
  • Remember 4s empties before 3d when forming ions, even though it fills first.
  • Distinguish shielding (inner electrons repelling outer ones) from nuclear charge (attracting them) — both affect radius and ionisation energy.
  • Atomic number = number of protons = number of electrons in a neutral atom.
  • Mass number = protons + neutrons; isotopes share atomic number but differ in mass number.
  • s sub-shells hold 2 electrons, p hold 6, d hold 10, f hold 14.
  • First ionisation energy: energy to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions.
  • Successive ionisation energies always increase, with big jumps marking a change of electron shell.
  • 4s fills before 3d but empties first when transition metals form ions.
  • Chromium is [Ar]3d5 4s1 and copper is [Ar]3d10 4s1 due to extra stability of half-full/full d sub-shells.
  • Ionisation energy dips slightly at group 3 (new p sub-shell) and group 6 (electron pairing) across a period.
  • Ionic bonding is electrostatic attraction between oppositely charged ions in a giant lattice.
  • Metallic bonding involves delocalised electrons and a lattice of positive ions, giving conductivity and malleability.
  • Dative bonding is a covalent bond where both electrons come from one atom, shown with an arrow.
  • Ionisation energy decreases down a group because increased atomic radius and shielding outweigh extra nuclear charge.
What is the atomic number of an element?
The number of protons in the nucleus, which equals the number of electrons in a neutral atom.
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Define isotopes.
Atoms of the same element with the same number of protons but different numbers of neutrons (different mass numbers).
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What is the maximum number of electrons in a p sub-shell?
6 electrons.
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State the full definition of first ionisation energy.
The energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions.
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Why do successive ionisation energies increase?
Each electron is removed from an increasingly positive ion, so electrostatic attraction to the nucleus is stronger.
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What do big jumps in successive ionisation energy data indicate?
A change of electron shell (moving to electrons closer to the nucleus with less shielding).
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Give the electron configuration of Fe2+.
[Ar]3d6 — the 4s electrons are removed first, before any 3d electrons.
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Why is chromium's configuration [Ar]3d5 4s1 rather than [Ar]3d4 4s2?
A half-full 3d sub-shell (5 electrons, one each) is more stable, so one 4s electron moves to 3d.
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Why does ionisation energy dip slightly between group 2 and group 3?
Group 3 elements start filling a new, higher-energy p sub-shell, so the electron is easier to remove.
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Why does ionisation energy dip slightly between group 5 and group 6?
Group 6 elements have paired electrons in a p orbital; electron-electron repulsion makes one easier to remove.
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What causes ionisation energy to decrease down a group?
Increased atomic radius and increased shielding from extra inner shells outweigh the increase in nuclear charge.
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What is metallic bonding?
Electrostatic attraction between delocalised electrons and a lattice of positive metal ions.
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What is a dative (coordinate) covalent bond?
A covalent bond where both shared electrons are donated by the same atom, shown with an arrow in diagrams.
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Why does graphite conduct electricity but diamond doesn't?
Graphite has delocalised electrons between layers that can move; diamond has all four outer electrons in fixed covalent bonds.
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How is relative atomic mass calculated?
As a weighted mean of the masses of all isotopes present, based on their percentage abundance, relative to carbon-12.
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Energetics, kinetics & equilibria

Enthalpy changes

Enthalpy change (ΔH) is heat energy transferred at constant pressure. Exothermic reactions release energy, ΔH is negative. Endothermic reactions absorb energy, ΔH is positive.

  • Standard enthalpy of formation ΔHf°: forming 1 mole of a compound from its elements in standard states (100 kPa, 298 K).
  • Standard enthalpy of combustion ΔHc°: burning 1 mole of a substance completely in oxygen under standard conditions.
  • Bond enthalpies are always positive (breaking bonds absorbs energy); making bonds releases energy.
  • Hess's Law: total enthalpy change is independent of the route taken. Use it to find ΔH indirectly via formation or combustion data.
  • q = mcΔT is used in calorimetry, where c for water is 4.18 J g⁻¹ K⁻¹. Common mistake: forgetting to convert mass of solution properly or using the wrong sign.
  • Mean bond enthalpy calculations: ΔH = (bonds broken) − (bonds made). These give estimates, not exact values, because mean bond enthalpies are averaged across many compounds.

Kinetics

Rate of reaction depends on collision theory: particles must collide with energy ≥ activation energy (Ea) and correct orientation.

  • Increasing temperature increases rate because more particles have energy ≥ Ea (Maxwell-Boltzmann distribution shifts right and flattens) — this has a much bigger effect than the small increase in collision frequency.
  • Catalysts provide an alternative route with lower Ea, increasing the proportion of successful collisions, without being used up.
  • Rate equations: rate = k[A]^m[B]^n. Orders must be found experimentally, never from stoichiometry.
  • Overall order = sum of individual orders. Units of k depend on overall order.
  • Rate-determining step is the slowest step; only reactants appearing in the rate equation (up to that step) affect rate.
  • The Arrhenius equation, k = Ae^(−Ea/RT), links rate constant to temperature and activation energy; a linear form (ln k vs 1/T) is used to find Ea from gradient = −Ea/R.

Equilibria

Dynamic equilibrium: forward and reverse rates are equal in a closed system, concentrations stay constant (not equal).

  • Le Chatelier's Principle predicts the direction of shift when conditions change, but does NOT explain the rate or the equilibrium constant Kc/Kp itself.
  • Kc is only affected by temperature; changing concentration, pressure or adding a catalyst does not change Kc, only the position of equilibrium (except catalysts, which change neither).
  • Kc = [products]/[reactants], each raised to its stoichiometric power, only for homogeneous equilibria (all species same physical state); pure solids and liquids are omitted from Kc expressions.
  • For an exothermic forward reaction, increasing temperature decreases Kc; for endothermic, increasing temperature increases Kc.
  • Common mistake: confusing Kc with the rate constant k, or forgetting units on Kc, which depend on the equilibrium expression.
  • pH and acid-base equilibria (Ka, Kw, pKa) link to this topic — remember Kw = 1.00 × 10⁻¹⁴ mol² dm⁻⁶ at 298 K.
  • ΔH is negative for exothermic reactions and positive for endothermic reactions, always quoted in kJ mol⁻¹.
  • Hess's Law states total enthalpy change is independent of the route taken between reactants and products.
  • Bond breaking always absorbs energy (positive); bond making always releases energy (negative).
  • q = mcΔT, with specific heat capacity of water c = 4.18 J g⁻¹ K⁻¹.
  • Reaction orders must be found experimentally from rate data, never assumed from the balanced equation.
  • The rate-determining step is the slowest step and determines which species appear in the rate equation.
  • Arrhenius equation: k = Ae^(−Ea/RT); a graph of ln k against 1/T gives gradient = −Ea/R.
  • Kc is affected only by temperature; concentration, pressure and catalysts never change its value.
  • Pure solids and liquids are left out of Kc and Kp expressions.
  • Increasing temperature increases Kc for an endothermic forward reaction and decreases it for an exothermic one.
  • Le Chatelier's Principle predicts equilibrium shift direction but does not explain reaction rate or Kc.
  • Kw = 1.00 × 10⁻¹⁴ mol² dm⁻⁶ at 298 K, the basis for pH and pOH calculations.
What is the sign of ΔH for an exothermic reaction?
Negative — energy is released to the surroundings.
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State Hess's Law.
The total enthalpy change for a reaction is independent of the route taken, as long as start and end conditions are the same.
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Why are bond breaking enthalpies always positive?
Breaking bonds requires an input of energy to overcome attractive forces, so it is always endothermic.
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Give the formula linking heat energy, mass, specific heat capacity and temperature change.
q = mcΔT (specific heat capacity of water = 4.18 J g⁻¹ K⁻¹).
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How must reaction orders be determined?
Experimentally, from initial rate or concentration-time data — never read off the balanced equation.
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What does the rate-determining step control?
It is the slowest step in a mechanism and determines which species appear in the experimental rate equation.
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State the Arrhenius equation.
k = Ae^(−Ea/RT), where A is the pre-exponential factor, Ea is activation energy, R is the gas constant and T is temperature in kelvin.
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How do you find activation energy from an Arrhenius plot?
Plot ln k against 1/T; the gradient equals −Ea/R, so Ea = −gradient × R.
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What single factor changes the value of Kc?
Temperature only — concentration, pressure and catalysts do not change Kc.
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Why are pure solids and liquids omitted from Kc expressions?
Their concentration (or activity) is constant, so they are incorporated into the value of Kc itself rather than written in the expression.
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What happens to Kc when temperature increases for an exothermic forward reaction?
Kc decreases, because the equilibrium shifts towards the reactants (the endothermic, reverse direction).
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What does Le Chatelier's Principle predict?
The direction equilibrium shifts when concentration, pressure or temperature changes, to oppose the change.
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What is the value of Kw at 298 K?
1.00 × 10⁻¹⁴ mol² dm⁻⁶.
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Why do catalysts increase reaction rate?
They provide an alternative reaction pathway with a lower activation energy, increasing the proportion of successful collisions, without being consumed.
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What effect does increasing temperature have on the Maxwell-Boltzmann distribution?
The curve shifts right and flattens, so more particles have energy ≥ activation energy, increasing rate.
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Redox & electrochemistry

Oxidation states

Oxidation state rules: uncombined elements = 0, simple ions = charge on the ion, oxygen is -2 (except -1 in peroxides, -1/2 in superoxides, and +2 in OF2), hydrogen is +1 (except -1 in metal hydrides like NaH), fluorine is always -1. All oxidation states in a neutral compound sum to zero; in an ion they sum to the ion's charge.

Oxidation and reduction

OILRIG: Oxidation Is Loss, Reduction Is Gain (of electrons). An oxidising agent gets reduced (gains electrons, its oxidation state falls); a reducing agent gets oxidised (loses electrons, its oxidation state rises). In a redox equation, the oxidation state changes must balance: electrons lost by one species equal electrons gained by the other.

Half-equations

Write half-equations separately for oxidation and reduction, balance atoms first, then charge using electrons, then combine so electrons cancel exactly. For reactions in acidic solution, balance oxygens with H2O and hydrogens with H+.

Electrode potentials

Standard electrode potential E-standard is measured against the standard hydrogen electrode (SHE, defined as 0.00V) at 298K, 100kPa, and 1.00 mol dm-3 solution concentration. A standard cell is two half-cells connected by a wire (electrons) and a salt bridge (ions, often KNO3-soaked filter paper) to complete the circuit without mixing solutions.

Cell EMF (E-cell) = E(positive electrode) - E(negative electrode), using the more positive minus the less positive (or the reduction potentials of the right-hand minus left-hand electrode as written). A more positive E-standard means a stronger oxidising agent (more likely to be reduced); a more negative E-standard means a stronger reducing agent.

Predicting feasibility

A reaction is feasible if E-cell is positive. Use E-cell to predict direction, but remember predictions from electrode potentials ignore kinetics: a reaction can be thermodynamically feasible yet too slow to observe (high activation energy), so real experiments do not always match the prediction.

Common mistakes

Mixing up which half-reaction is reversed when combining half-equations. Forgetting to scale electrons so they cancel before adding half-equations together. Getting E-cell the wrong way round (always more positive minus less positive, or right minus left as conventionally drawn). Confusing oxidation state change with actual charge on an ion. Forgetting that a negative E-cell means the reaction as written is not feasible, but the reverse reaction is.

Fuel cells and storage cells

Hydrogen fuel cells oxidise H2 at the negative electrode and reduce O2 at the positive electrode, producing only water; they are more efficient than burning fuel since they avoid heat-engine losses. Rechargeable cells (like Li-ion) can be recharged by reversing the cell reaction using an external supply; non-rechargeable cells cannot.

  • Standard hydrogen electrode (SHE) is defined as exactly 0.00V at 298K, 100kPa, 1.00 mol dm-3 H+.
  • OILRIG: Oxidation Is Loss of electrons, Reduction Is Gain of electrons.
  • E-cell = E(positive electrode) minus E(negative electrode), always the more positive value minus the less positive.
  • A reaction is thermodynamically feasible only if the calculated E-cell is positive.
  • The more positive an electrode potential, the stronger the species is as an oxidising agent.
  • The more negative an electrode potential, the stronger the species is as a reducing agent.
  • Standard conditions for electrode potentials are 298K, 100kPa, and 1.00 mol dm-3 solutions.
  • A salt bridge (often KNO3 in filter paper) completes the circuit by allowing ion flow without the two solutions mixing.
  • Feasibility from E-cell ignores kinetics, so a positive E-cell reaction can still be too slow to observe in practice.
  • Oxygen is -2 in almost all compounds, except -1 in peroxides and +2 in OF2.
  • Hydrogen is +1 in most compounds but -1 in metal hydrides such as NaH.
  • In hydrogen fuel cells, H2 is oxidised at the negative electrode and O2 is reduced at the positive electrode, giving water as the only product.
What does OILRIG stand for?
Oxidation Is Loss of electrons, Reduction Is Gain of electrons.
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What is the value of the standard hydrogen electrode potential?
Exactly 0.00V, by definition, under standard conditions (298K, 100kPa, 1.00 mol dm-3).
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How do you calculate E-cell from two electrode potentials?
E-cell = E(positive electrode) minus E(negative electrode) - the more positive value minus the less positive.
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What E-cell value indicates a feasible reaction?
A positive E-cell value; negative means the reaction as written is not feasible (but the reverse is).
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What does a more positive electrode potential tell you about a species?
It is a stronger oxidising agent - more likely to be reduced.
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What does a more negative electrode potential tell you about a species?
It is a stronger reducing agent - more likely to be oxidised.
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What is the role of a salt bridge in an electrochemical cell?
It completes the circuit by allowing ion flow between half-cells, without letting the two solutions mix.
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Why might a reaction predicted feasible by E-cell not actually happen?
Because E-cell predictions ignore kinetics - the reaction may have a high activation energy and be too slow.
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What is the oxidation state of oxygen in hydrogen peroxide?
-1 (peroxides are an exception to the usual -2 rule).
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What is the oxidation state of hydrogen in sodium hydride, NaH?
-1 (metal hydrides are an exception to the usual +1 rule).
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What happens at the negative electrode of a hydrogen fuel cell?
Hydrogen gas is oxidised, releasing electrons and forming H+ ions.
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What happens at the positive electrode of a hydrogen fuel cell?
Oxygen gas is reduced, combining with electrons and H+ ions to form water.
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What are the standard conditions used for measuring electrode potentials?
298K, 100kPa pressure, and 1.00 mol dm-3 solution concentration.
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What is a reducing agent in terms of electron transfer?
A species that loses electrons and gets oxidised itself, causing another species to be reduced.
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What must balance when combining two half-equations into a full redox equation?
The number of electrons lost in one half-equation must equal the number gained in the other, so scale them to cancel.
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Inorganic & periodicity

Periodicity: structure and trends

Period 3 (Na to Ar) shows how atomic structure controls physical properties.

  • Atomic radius decreases left to right across a period. Increasing nuclear charge pulls the same-shell electrons in tighter, and shielding stays roughly constant.
  • First ionisation energy generally increases across a period, but with two dips: Mg to Al (Al's outer electron is in a 3p orbital, higher energy and slightly shielded by the 3s pair, so easier to remove) and P to S (S has a paired 3p electron; the repulsion between the paired electrons makes it easier to lose than expected).
  • Melting points rise from Na to Al (giant metallic structures, more delocalised electrons per atom increase metallic bonding strength), peak at Si (giant covalent, strong covalent bonds throughout the lattice), then crash for P4, S8, Cl2 and Ar (simple molecular or monatomic, held only by weak van der Waals forces, so melting point depends on molecule size: S8 > P4 > Cl2 > Ar).

Reactions of Period 3 elements and oxides with water

  • Na and Mg react with water; Na reacts vigorously (2Na + 2H2O to 2NaOH + H2), Mg reacts very slowly with cold water but readily with steam to give MgO and H2.
  • Oxides across the period show a clear acid-base trend: Na2O and MgO are basic (form alkaline solutions or react with acids); Al2O3 is amphoteric (reacts with both acids and alkalis); SiO2 is acidic but insoluble; P4O10, SO2/SO3 are acidic, dissolving in water to give acidic solutions (e.g. SO3 + H2O to H2SO4).

Group 2: the alkaline earth metals

  • Reactivity increases down the group (Mg to Ba) because ionisation energy falls as atomic radius increases and shielding increases, so the outer electrons are lost more easily.
  • Reaction with water gets more vigorous down the group: Mg barely reacts with cold water, Ca reacts steadily, Ba reacts vigorously.
  • Solubility trends matter for exam calculations: hydroxides become MORE soluble down the group (Mg(OH)2 is only slightly soluble, giving milk of magnesia; Ba(OH)2 is quite soluble), while sulfates become LESS soluble down the group (MgSO4 is soluble, BaSO4 is essentially insoluble, used as the classic test for sulfate ions with acidified BaCl2).

Group 7: the halogens

  • Reactivity (oxidising power) decreases down the group as atomic radius increases and shielding increases, making it harder to attract an extra electron.
  • Displacement reactions demonstrate this: chlorine displaces bromine and iodine from their halide solutions; bromine displaces iodine only.
  • Test for halide ions: add acidified silver nitrate. Cl- gives a white precipitate (soluble in dilute NH3), Br- gives a cream precipitate (soluble in concentrated NH3 only), I- gives a yellow precipitate (insoluble in concentrated NH3).

Common mistakes

  • Writing 'ionisation energy decreases across the period' — it generally increases, only two specific dips exist.
  • Forgetting that halogen reactivity is about gaining electrons, so it decreases down the group, the opposite trend to Group 2 metal reactivity.
  • Mixing up sulfate (decreasing solubility down Group 2) with hydroxide (increasing solubility down Group 2).
  • Atomic radius decreases across Period 3 due to increasing nuclear charge with constant shielding.
  • First ionisation energy dips at Mg to Al (3p vs 3s) and at P to S (electron pairing repulsion).
  • Period 3 melting points peak at silicon (giant covalent) then drop sharply for P4, S8, Cl2, Ar (simple molecular).
  • Na2O and MgO are basic oxides; Al2O3 is amphoteric; SiO2, P4O10 and sulfur oxides are acidic.
  • Group 2 reactivity with water increases down the group: Mg reacts slowly, Ca steadily, Ba vigorously.
  • Group 2 hydroxide solubility increases down the group; sulfate solubility decreases down the group.
  • BaSO4 insolubility is the basis of the sulfate test using acidified BaCl2, forming a white precipitate.
  • Halogen reactivity (oxidising power) decreases down Group 7 as atomic radius and shielding increase.
  • Chlorine displaces bromide and iodide from solution; bromine displaces iodide only.
  • Silver nitrate test: AgCl is white (dissolves in dilute NH3), AgBr is cream (dissolves in conc. NH3), AgI is yellow (insoluble in conc. NH3).
  • Sodium reacts vigorously with cold water; magnesium reacts only slowly with cold water but readily with steam.
  • Amphoteric Al2O3 reacts with both dilute acids and dilute alkalis, showing it sits between basic and acidic oxides.
Why does atomic radius decrease across Period 3?
Nuclear charge increases while shielding stays roughly constant, so electrons in the same shell are pulled in more strongly.
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Why does first ionisation energy drop from Mg to Al?
Al's outer electron is in a higher-energy 3p orbital that is slightly shielded by the 3s electron pair, so it is easier to remove.
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Why does first ionisation energy drop from P to S?
Sulfur has two paired electrons in one 3p orbital; the extra repulsion between the paired electrons makes one easier to remove.
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Why do Period 3 melting points fall sharply after silicon?
Si is giant covalent with strong bonds throughout; P4, S8, Cl2, Ar are simple molecular, held only by weak van der Waals forces.
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Classify Na2O, Al2O3 and SiO2 as acidic, basic or amphoteric.
Na2O is basic, Al2O3 is amphoteric, SiO2 is acidic.
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How does Group 2 metal reactivity with water change down the group, and why?
It increases down the group because ionisation energy falls as atomic radius and shielding increase, so electrons are lost more easily.
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How does Group 2 hydroxide solubility change down the group?
It increases down the group; Mg(OH)2 is only slightly soluble while Ba(OH)2 is fairly soluble.
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How does Group 2 sulfate solubility change down the group?
It decreases down the group; MgSO4 is soluble but BaSO4 is essentially insoluble.
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What is the test for sulfate ions and what is the positive result?
Add dilute HCl then BaCl2 solution; a white precipitate of BaSO4 confirms sulfate.
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How does halogen reactivity change down Group 7, and why?
It decreases down the group because atomic radius and shielding increase, making it harder to attract an extra electron.
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What happens when chlorine water is added to potassium bromide solution?
Chlorine displaces bromine, giving an orange colour, because chlorine is the stronger oxidising agent.
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Silver nitrate test: colour and ammonia solubility for chloride, bromide, iodide precipitates.
AgCl white, dissolves in dilute NH3; AgBr cream, dissolves only in concentrated NH3; AgI yellow, insoluble even in concentrated NH3.
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How does magnesium react with cold water compared with steam?
Very slowly with cold water, but readily with steam to form MgO and hydrogen gas.
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What ion do amphoteric oxides like Al2O3 react with to prove they are amphoteric?
They react with both H+ ions (dilute acid) and OH- ions (dilute alkali).
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Organic chemistry I

Nomenclature and formulae

Organic chemistry runs on IUPAC naming. Learn the stem for chain length (meth-1, eth-2, prop-3, but-4, pent-5, hex-6) then the suffix for the functional group: -ane (alkane), -ene (alkene), -ol (alcohol), -al (aldehyde), -one (ketone), -oic acid (carboxylic acid), -oate (ester).

  • General formulae matter: alkanes CnH2n+2, alkenes CnH2n.
  • Empirical formula is the simplest whole-number ratio; molecular formula is the actual number of atoms; you get molecular from empirical using the Mr.
  • Displayed, structural, skeletal and general formulae are all examinable — practise converting between them.

Isomerism

Structural isomers share a molecular formula but differ in structure: chain, position and functional group isomers.

Stereoisomers share the same structural formula but atoms are arranged differently in space.

  • E/Z isomerism arises from restricted rotation around a C=C double bond and needs two different groups on each carbon of the double bond.
  • Use CIP (Cahn-Ingold-Prelog) priority rules based on atomic number to assign E (opposite sides, higher priorities) or Z (same side).
  • Common mistake: forgetting that cis-trans naming only works when each carbon carries an H; E/Z is the general system examiners want.

Reaction mechanisms

Alkanes undergo free-radical substitution with halogens in UV light: initiation (homolytic fission), propagation (two steps), termination. Learn to draw curly arrows showing single-barbed (radical) movement.

Alkenes undergo electrophilic addition, for example with bromine water (decolourises, test for unsaturation) or hydrogen halides. With unsymmetrical alkenes and HX, Markovnikov's rule applies: the major product has the halogen on the carbon that gives the more stable (more substituted) carbocation intermediate.

Practical skills and hazards

  • Alcohols are classified primary, secondary or tertiary by the carbon bonded to -OH; this determines oxidation behaviour (primary to aldehyde then acid, secondary to ketone only, tertiary resists oxidation) using acidified potassium dichromate(VI), which turns from orange to green.
  • Combustion and cracking (thermal or catalytic) of alkanes are key industrial reactions - cracking produces shorter alkanes and alkenes to meet fuel demand.
  • Common mistakes: mixing up homolytic and heterolytic fission, drawing curly arrows from atoms instead of bonds or lone pairs, and confusing empirical with molecular formula in calculations.
  • Alkanes follow the general formula CnH2n+2 and alkenes follow CnH2n.
  • Homologous series members differ by CH2 and share the same general formula and similar chemical properties.
  • E/Z isomerism requires two different substituents on each carbon of the C=C double bond, assigned using CIP priority rules by atomic number.
  • Free-radical substitution of alkanes with halogens needs UV light and proceeds via initiation, propagation and termination steps.
  • Electrophilic addition is the characteristic reaction of alkenes, shown by rapid decolourisation of orange bromine water.
  • Markovnikov's rule: with unsymmetrical alkenes and HX, the major product has the halogen bonded to the carbon that forms the more stable carbocation.
  • Primary alcohols oxidise to aldehydes then carboxylic acids; secondary alcohols oxidise only to ketones; tertiary alcohols are not oxidised by acidified dichromate(VI).
  • Acidified potassium dichromate(VI) changes colour from orange to green when it oxidises a primary or secondary alcohol.
  • Cracking (thermal or catalytic) breaks longer-chain alkanes into shorter alkanes and alkenes to match market fuel demand.
  • Homolytic fission gives two radicals (single-barbed curly arrows); heterolytic fission gives two ions (double-barbed curly arrows).
  • Structural isomers have the same molecular formula but different structural arrangement; stereoisomers share the same structural formula but differ in spatial arrangement.
  • Empirical formula is the simplest whole-number atom ratio; molecular formula is found by scaling the empirical formula using the molar mass, Mr.
What is the general formula for alkanes?
CnH2n+2
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What is the general formula for alkenes?
CnH2n
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What two conditions are needed for E/Z isomerism on a C=C bond?
Restricted rotation around the double bond, and each carbon of the double bond must carry two different substituents
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What are the three stages of free-radical substitution?
Initiation, propagation and termination
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What condition is required to start free-radical substitution of alkanes with halogens?
UV light, to homolytically break the halogen-halogen bond
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What colour change indicates a positive test for a C=C double bond with bromine water?
Orange bromine water rapidly decolourises to colourless
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State Markovnikov's rule.
When HX adds to an unsymmetrical alkene, the major product has the halogen on the carbon that forms the more stable (more substituted) carbocation
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What does primary alcohol oxidation with acidified dichromate(VI) produce, given excess oxidising agent?
First an aldehyde, then further oxidised to a carboxylic acid
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What does secondary alcohol oxidation with acidified dichromate(VI) produce?
A ketone only, no further oxidation possible
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Why do tertiary alcohols resist oxidation by acidified dichromate(VI)?
There is no hydrogen on the carbon bonded to the -OH group for the oxidising agent to remove
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What colour change shows acidified potassium dichromate(VI) has oxidised an alcohol?
Orange changes to green
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What is cracking used for industrially?
Breaking longer-chain alkanes into shorter, more useful alkanes and alkenes to match fuel and feedstock demand
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What is the difference between homolytic and heterolytic fission?
Homolytic fission splits a bond evenly to give two radicals (shown with single-barbed arrows); heterolytic fission splits a bond unevenly to give two ions (shown with double-barbed arrows)
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What is the difference between structural isomers and stereoisomers?
Structural isomers have the same molecular formula but different structural arrangement of atoms; stereoisomers have the same structural formula but different spatial arrangement
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How do you find a molecular formula from an empirical formula?
Divide the compound's Mr by the empirical formula mass to get a whole-number multiplier, then multiply each atom count in the empirical formula by it
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Organic chemistry II & analysis

Aldehydes and ketones

Both contain the carbonyl group C=O. Aldehydes have it at the end of the chain (CHO) and are made by oxidising primary alcohols; ketones have it mid-chain (C=O flanked by two carbons) and come from secondary alcohols.

  • Test to tell them apart: Tollens' reagent (ammoniacal silver nitrate) gives a silver mirror with aldehydes only, as the aldehyde is oxidised to a carboxylic acid.
  • Fehling's solution turns from blue Cu2+ to a brick-red Cu2O precipitate with aldehydes; ketones give no change.
  • Both react with 2,4-dinitrophenylhydrazine (2,4-DNP) to give an orange precipitate, confirming a carbonyl is present (but not which type).
  • Reduction: NaBH4 reduces aldehydes to primary alcohols and ketones to secondary alcohols.
  • Nucleophilic addition with HCN (via KCN + dilute acid) forms hydroxynitriles; the mechanism involves the CN- nucleophile attacking the delta-positive carbonyl carbon.

Carboxylic acids and esters

Carboxylic acids (COOH) are weak acids, reacting with carbonates to fizz CO2, with metals to give H2, and with alcohols (conc. H2SO4 catalyst, reflux) to form esters plus water in condensation reactions. Esters are hydrolysed by acid (reversible, gives acid + alcohol) or base (irreversible, gives carboxylate salt + alcohol - this is saponification).

Aromatic chemistry (benzene)

Benzene, C6H6, has a delocalised ring of six pi electrons above and below the plane, making all six C-C bonds equal length (139 pm, between single 154 pm and double 134 pm). This delocalisation makes benzene more stable than the Kekule model predicts by about 150 kJ/mol (from enthalpy of hydrogenation data), and explains why benzene undergoes electrophilic substitution, not addition - substitution keeps the stable ring intact.

  • Nitration: benzene + conc. HNO3/conc. H2SO4 catalyst, 50 degC, gives nitrobenzene; the electrophile is NO2+.
  • Friedel-Crafts acylation: benzene + acyl chloride, AlCl3 catalyst, anhydrous reflux, gives a phenyl ketone; used to add a carbon side chain since benzene cannot do simple addition reactions.

Amines, amides, amino acids and polymers

Amines are bases (lone pair on N). Amino acids are amphoteric, existing as zwitterions at neutral pH. Condensation polymers: polyesters (diol + dicarboxylic acid, ester links) and polyamides (diamine + diacid or diacyl chloride, amide links, e.g. nylon).

Organic analysis

  • Mass spectrometry: molecular ion peak (M+) gives Mr; fragmentation pattern helps identify structure.
  • IR spectroscopy: identifies functional groups from absorption at characteristic wavenumbers, e.g. C=O around 1680-1750 cm-1, O-H (acid) broad 2500-3300 cm-1, O-H (alcohol) broad 3200-3550 cm-1, N-H 3300-3500 cm-1.
  • NMR: chemical shift (ppm, relative to TMS at 0), integration trace gives relative proton ratios, splitting patterns follow the n+1 rule (a peak is split into n+1 lines by n adjacent, non-equivalent protons).

Common mistakes

  • Confusing Tollens' (silver mirror) with Fehling's (brick-red precipitate) - know both.
  • Forgetting 2,4-DNP only shows a carbonyl is present, not aldehyde vs ketone.
  • Writing benzene with alternating double bonds instead of a delocalised ring in mechanisms.
  • Forgetting acid hydrolysis of esters is reversible but base hydrolysis is not.
  • Tollens' reagent gives a silver mirror with aldehydes only, not ketones.
  • Fehling's solution turns brick-red (Cu2O) with aldehydes, stays blue with ketones.
  • 2,4-DNP gives an orange precipitate with any carbonyl (aldehyde or ketone) but cannot distinguish them.
  • NaBH4 reduces aldehydes to primary alcohols and ketones to secondary alcohols.
  • Benzene's C-C bond length is 139 pm, uniform, between single (154 pm) and double (134 pm) bond lengths.
  • Benzene is about 150 kJ/mol more stable than the Kekule structure predicts, from enthalpy of hydrogenation evidence.
  • Benzene undergoes electrophilic substitution, not addition, to preserve the stable delocalised ring.
  • Nitration of benzene uses conc. HNO3 and conc. H2SO4 at 50 degC, with NO2+ as the electrophile.
  • Friedel-Crafts acylation uses an acyl chloride with AlCl3 catalyst under anhydrous conditions.
  • Ester hydrolysis with acid is reversible; hydrolysis with base (saponification) is irreversible.
  • Amino acids exist as zwitterions at neutral pH, being amphoteric.
  • In NMR, an n+1 splitting rule means a proton's peak is split into n+1 lines by n adjacent non-equivalent protons.
How do you distinguish an aldehyde from a ketone using Tollens' reagent?
Aldehydes give a silver mirror (oxidised to carboxylic acid); ketones give no reaction.
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What colour change does Fehling's solution show with an aldehyde?
Blue Cu2+ solution turns to a brick-red Cu2O precipitate.
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What does a positive 2,4-DNP test tell you?
An orange precipitate confirms a carbonyl group (C=O) is present, but not whether it is an aldehyde or ketone.
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What does NaBH4 do to an aldehyde?
Reduces it to a primary alcohol.
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What does NaBH4 do to a ketone?
Reduces it to a secondary alcohol.
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What is the bond length evidence for benzene's structure?
All C-C bonds are 139 pm, equal length, between a single bond (154 pm) and double bond (134 pm), showing delocalisation.
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How much more stable is real benzene than the Kekule (cyclohexatriene) model predicts?
About 150 kJ/mol, shown by comparing enthalpies of hydrogenation.
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Why does benzene undergo substitution rather than addition reactions?
Addition would destroy the stable delocalised pi ring system, so substitution (keeping the ring intact) is energetically favoured.
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What are the conditions and electrophile for nitration of benzene?
Conc. HNO3 and conc. H2SO4 catalyst at 50 degC; the electrophile is NO2+.
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What catalyst and conditions are used for Friedel-Crafts acylation?
AlCl3 catalyst with an acyl chloride, anhydrous conditions, under reflux.
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What is the difference between acid and base hydrolysis of an ester?
Acid hydrolysis is reversible, giving carboxylic acid and alcohol; base hydrolysis is irreversible (saponification), giving a carboxylate salt and alcohol.
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What is a zwitterion?
A molecule (such as an amino acid at neutral pH) with both a positive and negative charge on different atoms, overall neutral.
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What is the n+1 rule in NMR splitting?
A proton's signal is split into n+1 peaks by n adjacent, non-equivalent protons.
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What IR wavenumber range is characteristic of a C=O bond?
Approximately 1680-1750 cm-1.
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How do polyesters and polyamides differ in their linking group?
Polyesters form ester links (from a diol and dicarboxylic acid); polyamides form amide links (from a diamine and diacid or diacyl chloride).
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